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n200080 [17]
3 years ago
8

2(4 + 2x) ≥ 5x + 5? please help

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
2(4 + 2x) ≥ 5x + 5

First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4. 
8 + 4x \ge 5x + 5

Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself. 
8 \ge 5x + 5 - 4

Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.
8 \ge x + 5

Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3. 
3 \ge x

Fifth, we can switch sides now to get the result of this problem.
x \le 3

Answer: x \le 3
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Answer:

The numerical limits for a B grade is between 81 and 89.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So

Z = \frac{X - \mu}{\sigma}

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X - 79.7 = 8.4*1.127

X = 89

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Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So

Z = \frac{X - \mu}{\sigma}

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Answer:

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Step-by-step explanation:

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∴ The brace is 2\sqrt{41} ≅ 12.806 ft long

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