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Artist 52 [7]
3 years ago
13

What is the solution to 3|–3x + 9| = –18?

Mathematics
2 answers:
givi [52]3 years ago
8 0

Answer:

No solution

Step-by-step explanation:

tresset_1 [31]3 years ago
5 0

Answer:

x=5 and x=1

Step-by-step explanation:

3 |-3x + 9| = -18

/3 /3

|-3x + 9| = -6

-3x + 9 = -6 -3x + 9 = 6

-9 -9 -9 -9

-3x = -15 -3x = -3

/-3 /-3 /-3 /-3

x = 5 and x = 1

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Find the rate of change, (y2-y1)/(x2-x1), from the data given...

(2.16-1.26)/(12-7)=0.18

(1.26-0.72)/(7-4)=0.18

Since the rate is constant, this is a linear equation of the form y=mx+b.  Furthermore, since 0 pencils cost 0, b=0, so the cost of the pencils is simply the number of pencils times 18 cents...

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3 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
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Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

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Step-by-step explanation:

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