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Sergeeva-Olga [200]
3 years ago
8

-2(7 – n) + 4 What is the answer to this any body know it??????????

Mathematics
2 answers:
Leni [432]3 years ago
7 0
2x-10 is the answerr
BartSMP [9]3 years ago
7 0

Answer:

2<em>n</em>+10

Step-by-step explanation:

you just distribute the -2 and you get -14+2<em>n</em>+4 and then add and you'll get 2<em>n</em>+10

if you are solving for the variable <em>n </em>then you would want your equation like this 2<em>n</em>+10=0

next you would put the 10 on the other side of the equation and have 2n=-10

finally you would divide by 2 and get n=-5

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Put the following equation of a line into slope-intercept form, simplifying all fractions. 4y - 4x -32​
MariettaO [177]

Answer:

y=-4x+4x-32

Step-by-step explanation:

3 0
3 years ago
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A sports store has 468 golf balls. They will be put into boxes that hold 18 balls each. What is the minimum number of boxes need
Alona [7]
468/18 = 26

Therefore they need at least 26 boxes to hold all the golf balls.

Hope this helps :)
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Write the equation of the line in slope-intercept form that has the following points: (4, 5) (-1, 2)
Dima020 [189]

Answer:

C. y = 3/5x + 13/5

Step-by-step explanation:

8 0
3 years ago
State whether the given equation or function is linear. Write yes or no. Explain your reasoning. f(x) = 7x2 + 4
vagabundo [1.1K]

For this case we have the following function:

f (x) = 7x ^ 2 + 4

By definition, we have that a linear equation is of the form y = mx + b

On the other hand, a quadratic equation is of the formy = ax ^ 2 + bx + c

Then, the given equation is not a linear equation, it is not of the form y = mx + b

Answer:

No, the equation is not linear. It is not of the form f (x) = mx + b.

4 0
3 years ago
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Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
3 years ago
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