Answer:
Tn = 64-4n
Step-by-step explanation:
The nth term of an AP is expressed as:
Tn = a+(n-1)d
a is the common difference
n is the number of terms
d is the common difference
Given the 6th term a6 = 40
T6 = a+(6-1)d
T6 = a+5d
40 = a+5d ... (1)
Given the 20th term a20 = -16
T20 = a+(20-1)d
T20 = a+19d
-16 = a+19d... (2)
Solving both equation simultaneously
40 = a+5d
-16 = a+19d
Subtracting both equation
40-(-16) = 5d-19d
56 = -14d
d = 56/-14
d = -4
Substituting d = -4 into equation
a+5d = 40
a+5(-4) = 40
a-20 = 40
a = 20+40
a = 60
Given a = 60, d = -4, to get the nth term of the sequence:
Tn = a+(n-1)d
Tn = 60+(n-1)(-4)
Tn = 60+(-4n+4)
Tn = 60-4n+4
Tn = 64-4n
Answer: i cannot see anything take a closer picture
Step-by-step explanation:
Answer:
3 for the first one 2ed one is 5
Step-by-step explanation:
Answer:
that is a whole lot of simple intrest
Answer:
a² = b² -w² +2wx
Step-by-step explanation:
The algebra is pretty straightforward. Expand the expression in parentheses and add x².
b² -(w -x)² = e² = a² -x²
b² -(w² -2wx +x²) = a² -x² . . . . . expand the square
b² -w² +2wx -x² = a² -x² . . . . . . distribute the minus sign
b² -w² +2wx = a² . . . . . . . . . . . . add x²