No, not reasonable.
98.3 divides by 52.6
Brady used compatible numbers 100 divided by 5 =20
He should've used 100 divided by 50 = 2
I’m not sure if I get the question, but the second one would be a fact and the others are all statements. I hope this helps :)
To solve the
following problems, we use the binomial probability equation:
P (r) = [n!/(n-r)!
r!] p^r q^(n-r)
where,
n = total
number of households = 8
r = number of
sample
p =
probability of success = 65% = 0.65
q = probability
of failure = 0.35
A. r = 5
P (r=5) = [8!
/ 3! 5!] 0.65^5 0.35^3
P (r=5) =
0.28
B. r >5
P (r=6) = [8!
/ 2! 6!] 0.65^6 0.35^2
P (r=6) =
0.26
P (r=7) = [8!
/ 1! 7!] 0.65^7 0.35^1
P (r=7) =
0.14
P (r=8) = [8!
/ 0! 8!] 0.65^8 0.35^0
P (r=8) =
0.03
Therefore
total is:
P (r>5) = 0.26
+ 0.14 + 0.03 = 0.43
C. r ≤ 5
P (r ≤ 5) = 1
- P (r>5)
P (r ≤ 5) = 1
– 0.43
P (r ≤ 5) =
0.57
<span> </span>
Answer:
50%
Step-by-step explanation:
The probability of picking a grapefruit is the amount of grapefruits over the amount of total fruit. There are 3 grapefruits, and 6 total pieces of fruit. 3/6 is equal to 1/2, so the probability is 1/2 or 0.5 or 50%.
