We know that
<span>The quotient of
-8x</span>²y³/xy=-8xy²
then
<span>the product of
(4xy)*z= -8xy</span>²------> z=-8xy²/(4xy)-----> z=-2y
the answer is
-2y
so
The quotient of -8x²y³/xy is same as the product of (4xy)*(-2y)
The area of a circular sector is <span>. </span>
<span>==> </span>
<span>Since r = s/2, it follows that </span><span>, or </span><span>, or </span>
<span>.
</span>
Answer:
D. (y +4)² = -4(x -2)
Step-by-step explanation:
The directrix is a vertical line, and the focus is to the left of it. The parabola will open to the left.
The vertex is halfway between the focus and directrix, so is located on the same horizontal line as the focus, at ...
x = (1 +3)/2 = 2
The focus to vertex distance is the difference in x-coordinates: 1 -2 = -1. This is the value of p in the form ...
(y -k)² = 4p(x -h) . . . . . . . parabola with vertex (h, k)
The equation is ...
(y +4)² = -4(x -2)
_____
<em>Additional comment</em>
Once you determine that the directrix is a vertical line, you know the equation will have a y² term. The only answer choice that has that is D.
Answer:
<h2>3seconds</h2>
Step-by-step explanation:
If a ball thrown downward from a window in a tall building is modeled by the equation, s = 16t² + 32t where s in feet, in order to know the time it will take to fall a distance of 276, we will substitute s = 276feet into the equation and calculate for the value of t as shown;
276 = 16t² + 32t
16t² + 32t = 276
Dividing through by 4
4t² + 8t = 69
4t² + 8t - 69 = 0
Using the general formula to find t
t = -b±√b²-4ac/2a
a = 4, b = 8 and c = -69
t = -8±√8²-4(4)(-69)/2(4)
t = -8±√64+1104/8
t = -8±√1168/8
t = -8±34.176/8
t = -8+34.176/8 or -8-34.176/8
t = 3.272 or -5.272
neglecting the negative time, t = 3secs to the nearest seconds
It will take the all 3secs to fall 276 feets
So for this equation you will want to graph the points (5,-2) and (8,4). I have taken the liberty of doing the graph for you.
With this I have put the two dots on the 2 locations they wanted. So then what you need to do is draw a straight line from dot one to dot two.