Answer: C. 254
Step-by-step explanation: All engineers is the population so this is stats and the number that chose math no matter what kind of engineer is 254
Answer:
Step-by-step explanation:
Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.
1) (2-6i)+(4+2i)
open the parenthesis
= 2-6i+4+2i
collect like terms
= 2+4-6i+2i
= 6-4i
2) (6+5i)(9-2i)
= 6(9)-6(2i)+9(5i)-5i(2i)
= 54-12i+45i-10i²
= 54+33i-10i²
In complex number i² = -1
= 54+33i-10(-1)
= 54+33i+10
= 54+10+33i
= 64+33i
3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i
= 2/3-9i*3+9i/3+9i
=2(3+9i)/(3-9i)(3+9i)
= 6+18i/9-27i+27i-81i²
= 6+18i/9-81(-1)
= 6+18i/9+81
= 6+18i/90
= 6/90 + 18i/90
= 1/15+1/5 i
4) For (3 − 5i)(7 − 2i)
open the parenthesis
= 3(7)-3(2i)-7(5i)-5i(-2i)
= 21-6i-35i+10i²
= 21-6i-35i+10(-1)
= 21-41i-10
= 11-41i
Answer:
f(5)=4
Step-by-step explanation:
f(5)=5_1=4
.....
So it’s saying that the following set in roster form: (1) N = (x :x is an odd number, 21< × ≤ 35,×€ N)?
It seems to be that the Roster form would do not do anything but the thing is that this listing would give us the output of a set from this problem.
Your answer would be, N = Set of Odd Numbers such that x is greater than 21 and less than or equal to 35 = {23, 25, 27, 29, 31, 33, 35}.
If you divide 61 by 66, you will get .9242424. The thousandths place is the third number, so you base it off of the four number. If the fourth number is under 5, the third number stays the same and all numbers after it disappear. If the number is above 5, the third number rounds up 1 and the rest disappear. Because the 3rd number is 4 and the 4th number is 2, you will get the answer of .924
