The length of the rope in this case becomes the radius of the circle that the goat is able to graze. The area of the circle is calculated through the equation,
A = πr²
Substituting,
A = π(5m)² = 78.54 m²
Thus, the area that the goat is able to graze is equal to 78.54 m².
The GCF of 14abc and 28a^2 b^2 c^3 would be the second option, 14abc.
How? We need to find the "Greatest Common Factor".
So between 14 & 28 is 14, and between a and a^2 is A, between b and b^2 is B, and c between c^3 is C, obviously.
That would leave us with 14abc, which we would consider the greatest common factor.
The correct option among the other answer choices is as follows: B.
Answer:
Step-by-step explanation:
For i figure
Radius=9×10^3
Diameter=18×10^3
For j figure
Radius=1m
Diameter=2m
For k
Radius=17×10^-2
Diameter=34×10^-2
For l
Radius=25×10^-3
Diameter=50×10^-3
Answer:
x^2-8x+16
Step-by-step explanation:
(x-4)^2
x^2-4x-4x+16
x^2-8x+16