This is the factor tree check oit the pic to find out
Answer:
The answer to your question is letter B.
Step-by-step explanation:
The correct answer is letter B because both Copper and Iron as reactants have an oxidation number of zero and when they have reacted their oxidation numbers would be different from those.
A redox reaction is a reaction that involves a transfer of electrons from one atom to another and the oxidation numbers of the reactants are different from the oxidation numbers from the products.
Answer:
Step-by-step explanation:
a) the equation representing the parabola is expressed as
h = -16t² - 4t + 20
c) to determine the height after 25 seconds, we would substitute 25 for t into the given equation. It becomes
h = -16(25)² - 4(25) + 20
h = - 10000 - 100 + 20
h = - 10080
d) when the coin lands on the ground, the height would be 0. Therefore,
-16t² - 4t + 20 = 0
Dividing both sides of the equation by 4, it becomes
- 4t² - t + 5 = 0
- 4t² - 5t + 4t + 5 = 0
- t(4t + 5) + 1(4t + 5) = 0
- t + 1 = 0 or 4t + 5 = 0
t = 1 or t = - 5/4
Since t cannot be negative, then t = 1 second
Answer:
A. change in a dependent variable
Answer:
-3
Step-by-step explanation:
Bring -2 to the other side and A to the other side
<em>-</em><em>2</em><em> </em><em>Become </em><em>2</em><em> </em><em>because </em><em>of </em><em>flipping</em>
<em>And </em><em>A </em><em>becomes </em><em>-A </em><em>because </em><em>of </em><em>flipping</em>
<em>2</em><em>-</em><em>2</em><em>+</em><em>3</em><em>=</em><em>-A</em>
<em>Flip </em><em>the </em><em>whole </em><em>equation </em><em>to </em><em>avoid </em><em>confusion</em>
<em>-A=</em><em>2</em><em>-</em><em>2</em><em>+</em><em>3</em>
<em>-</em><em>A=</em><em>+</em><em>3</em>
Bring the minus sign to the other side,
<u>A=-3</u>
<u>-</u><u>3</u><u> </u><u>-</u><u>2</u><u> </u><u>+</u><u>3</u><u> </u><u>=</u><u> </u><u>-</u><u> </u><u>2</u>
<u>Which </u><u>make </u><u>the </u><u>statement</u><u> </u><u>correct.</u>
<u>I hope </u><u>this </u><u>explanation</u><u> </u><u>helps, dont hesitate to ask for any question.Mark me as brainliest is appreciated.Tq!!</u>
