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Kobotan [32]
3 years ago
13

What is the least common denominator of 1/3 and 4/7?

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

21

Step-by-step explanation:

The denominators are 3 and 7 and those are both odd numbers.

You can not get a number lower than 21. Therefore 21 is the LCM (Lowest common denominator.)  

Hope this helps :)

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Alguém me ajuda rapido por favor tou aki rachando a cuca e n consigo
Lady bird [3.3K]

The vertices of a right triangle are (–6, 4), (0, 0), and (x, 0). Find the value of x.

4 0
4 years ago
When creating lines of best fit, do you believe that estimation by inspection of the equation is best or do you think it should
Alex73 [517]

Answer:

Estimation by inspection is better than trying to determine the line of best fit exactly

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

Step-by-step explanation:

To create lines of best fit the estimation by inspection is better than trying to determine the line of best fit exactly .

This is because line of best fit only shows the trend of the data and in most cases it doesn't have to start from origin.

Scenarios :

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

8 0
3 years ago
The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp
Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)

P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})

P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})

From Z tables:

P(31000 < X

P(31000 < X

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0
3 years ago
What is the answer to -4(5x6)
Softa [21]
<span>-4(5x6)
=</span><span>-4(30)
= - 120</span>
8 0
3 years ago
38+-72<br><br> Please help on this
AysviL [449]
38 + -72 = ?
? = -34

5 0
3 years ago
Read 2 more answers
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