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Zolol [24]
3 years ago
9

Find equations of both the tangent lines to the ellipse x^2 + 4y^2 = 36 that pass through the point (12, 3).y = (smaller slope)y

= (larger slope).
Mathematics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

x+y=15

Step-by-step explanation:

Given equation of x^2+4y^2=36

Differentiating both side 2x+8y\frac{dy}{dx}=0

\frac{dy}{dx}=\frac{-x}{4y}

It passes through the point (12,3) so

\frac{dy}{dx}=\frac{-12}{4\times 3}=1

So equation of tangent passing through (12,3) is

y-12=-1(x-3) as y-y_1=-m(x-x_1)

So x+y =15 will be the equation of tangent which passes though the point (12,3)

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