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garik1379 [7]
3 years ago
11

What is 294 miles every 14 gallons

Mathematics
1 answer:
azamat3 years ago
3 0
294 miles per 14 gallons = 21 miles per 1 gallon
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I’m confused on this question, please help me. (Ignore the black coloring, sorry.)
neonofarm [45]
To answer this question you will find out the total number of cupcakes donated and then calculate the amount of each flavor based on the percentage that is stated.

Here are the steps:

1. 12 x 10 x 12 (12 classes each donating 10 dozen) = 1440

2. 0.55 x 1440 (55% are chocolate) = 792 chocolate

3. 1440 - 792 (the remaining number of cupcakes)=648

4. 1/3(33 1/3%) x 648 = 216 red velvet

5. 1440 - 792 (chocolate) - 216 (red velvet) = 432 vanilla cupcakes

Chocolate-792
Red velvet - 216
Vanilla - 432

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3 years ago
Pls help me calculate the inverse of y equals 2x over x-7
NeTakaya
Y = 2x/x-7

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Nitella [24]
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\log_{4} x + \log_{4} (x+5) = 6
irina1246 [14]
       log(4)x + log(4)(x + 5) = 6
log(4)x + log(4)x + log(20) = 6
               log(8)x + log(20) = 6
               <u>            - log(20)  - log(20)</u>
                              <u>log(8)x</u> = <u>6 - log(20)</u>
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8 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
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