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faltersainse [42]
3 years ago
7

An entrepreneur estimates his total profit (total revenue minus total cost) for his proposed company as p(x) = x3 − 4x2 + 5x − 2

0, where p is in hundreds of dollars and x is number of years the company has been in business. In which year (x) will the entrepreneur break even?
a)year 1
b)year 2
c)year 3
d)year 4
Mathematics
2 answers:
nikitadnepr [17]3 years ago
7 0
To "break even" means that the costs are equal to the money made, so profit would have to be 0. Therefore, we can rewrite the equation to be
0 = x3 -4x2 +5x -20

From here, all you have to do is factor to be able to solve for the values of x

First, since the first two numbers both have an x2, we can factor that out
x2(x-4) + 5x -20 = 0

The next two can factor out a 5
x2(x-4) + 5(x-4) =0

Since both of these terms share an (x-4), they can be factored to become:
(x-4) (x2 +5) = 0

So now we just solve for x, and get x = 4, and +- (sqrt) 5i

Since 4 is the only answer present in the options (and since 5i is a non-real number), the answer would be 4

ANS: D

Hope this helped ^-^
shtirl [24]3 years ago
5 0

The correct answer is

Year 4

:)


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A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
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  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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