When forming a perfect square trinomial you need to "complete the square".
All of the steps to completing the square when solving an equation:
1. The leading coefficient must be 1.
2. Divide b by 2.
3. Square (b/2)
4. Add (b/2)^2 to both sides to keep the polynomial balanced.
5. You can now write the perfect square trinomial and solve.
x^2 - 3x
-3/2
(-3/2)^2 = 9/4 = 2 1/4
LETTER B
Answer:
(A) 3(2k+4h)
Step-by-step explanation:
I hope it helps .
let's first off apply a log rule of cancellation, keeping in mind that, first off is ln(), not in(), and that ln() is just a shortcut to logₑ.
![\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ e^{ln(x)}\implies e^{log_e(x)}\implies x \\\\\\ \cfrac{d}{dx}\left[ e^{ln(x)} \right]\implies \cfrac{d}{dx}[x]\implies 1](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%0A%5C%5C%5C%5C%0Alog_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7B%5Cdownarrow%20%7D%7D%7Ba%5E%7Blog_a%20x%7D%3Dx%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0Ae%5E%7Bln%28x%29%7D%5Cimplies%20e%5E%7Blog_e%28x%29%7D%5Cimplies%20x%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20e%5E%7Bln%28x%29%7D%20%5Cright%5D%5Cimplies%20%5Ccfrac%7Bd%7D%7Bdx%7D%5Bx%5D%5Cimplies%201)
Answer:
n < -14
Step-by-step explanation:
6 (n+2) < -72
6n + 12 < -72
6n < -72 - 12
6n < -84
n < -84/6
n < -14
So in distributive property you multiply the outside number by the two inside so in this case 2(a) + 2(-2) = 3(a) + 3(-5)
Which will give you
2a+ - 4 = 3a + - 15
Or
2a-4=3a-15
Then if your solving for a your can subtract 3a from 2a giving you
- a-4=-15
Then add 4 to - 15
-a =-11
Then divide by negative 1 (this is so a isn't negative)
A=11
Hope this helps!
