Answer:
-8>x>6
Step-by-step explanation:
I 5x+5I +22> 57subtract 22 on both sides
I5x+5I >35
SPLIT
5x+5>35 5x+5< -35 ( flip sign and 35 negative)
5x>30 5x< -40
x>6 x< -8
Draw a number line Write zero in the middle
From zero count to the left until- 8 make an open circle because- 8 is not included From -8 draw an arrow to the left (because x is less than -8)
From zero count to the right until 6 Make an open circle bc 6 is not included. From 6 draw an arrow to the right (because x is more than 6)
PART 2 is not already solved?
If you need to solve fot t
Divide both parts by pr
t= (l/ pr)
Answer:
$43.20
Step-by-step explanation:
If each family member buys one ticket and one lunch, then for ticket price t we have the total expenditure as ...
5(t +6.50) = 248.50
t +6.50 = 49.70 . . . . . divide by 5
t = 43.20 . . . . . . . . . . subtract 6.50
The price of each train ticket is $43.20.
Answer:
28
Step-by-step explanation:
Hope this helped.
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
