Can i get brainliest if my answer is true hehehehe :p
Answer:
a)
if 1 quarter = $ 0.25
1 dime = $ 0.10
1 penny = $ 0.01
so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar
therefore we say;
1 Quarter + 8 dimes + 3 penny
: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )
: 0.25 + 0.80 + 0.03 = $ 1.08
b)
Now if you have a 4 Quarters, you have change for $1.
If you have 5 dimes, you have change for 2 Quarters.
If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.
If you have 5 pennies, you have enough change for 1 nickel
Therefore
(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x
(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x
x = 0.75 + 0.4 + 0.04
x = $ 1.19
PROVED
What are the numbers for the other ones?
Answer:
.03
Step-by-step explanation:
The answer would be .03 as you are dividing .24 by 8, which would be 3 if there was no decimal point. Though, .24 is two places past the ones place so the answer would have to be two places past the ones place. If you divide it, 8 can't go into 2, so you would put a 0 above it. Though, 8 can go into 24 three times, so you would put three. Therefore, your answer would be .03 as it is two places past the ones place and if it is multiplied by 8, it would make .24, or 24 tenths.