Answer:
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Step-by-step explanation:
Volume V = length l^3
V = x^3
Differentiating both sides;
dV/dt = 3x^2 dv/dt
Given;
x = 10 in
dx/dt = 0.5 in/sec
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
The answer is B. It’s not too difficult
Answer:
B. 74 / 100
Explanation:
I got it right on the test :)
Answer:
see below. The solution is the doubly-shaded area.
Step-by-step explanation:
Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.
Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.