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3 years ago

Consider circle C with diameter DE. The equation of circle C is ()2 + ()2 = .

Mathematics

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer:

The equation of circle C is ( x-5 )2 + ( y-7 )2 = 80 .

Step-by-step explanation:

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Answer:

The frequency is relatable

Step-by-step explanation:

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3 years ago

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Please help -2x++8-6=-32

arlik [135]

Answer:

x = 17

Step-by-step explanation:

-2x+8-6=-32

lets isolate the x variable:

-2x=-32-8+6

-2x = -34

x= -34/-2

x= 34/2

x= 17

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3 years ago

Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

8 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

5 0

2 years ago

Emmett bought 10 packages of cat food and 3 packages of dog food. Each package of cat food contained 10 cans, and each package o

xz_007 [3.2K]

Answer: Emmet bought 94 more cans of cat food than dog food.

Step-by-step explanation:

4 0

3 years ago

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