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3 years ago

Need help worth 34 points!

Mathematics

2 answers:

exis [7]3 years ago

6 0

x + y = 3
- x - x
y = -x + 3

y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
y + 1 = -1(x + 1)
y + 1 = -1(x) - 1(1)
y + 1 = -x - 1
- 1 - 1
y = -x - 2

The answer is B.

NikAS [45]3 years ago

6 0

Answer:

the answer is b

Step-by-step explanation:

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2 years ago

Find dy/dx using first principle<br>x+1/x

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Answer:

The derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

Step-by-step explanation:

The first principle is given by:

$f'(x)=\frac{dy}{dx}=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

The function here is:

$f(x)=x+\frac{1}{x}$

Now, using the first principle we have:

$f'(x)=lim_{h\rightarrow 0}\frac{(x+h)+\frac{1}{(x+h)}-x-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h+\frac{1}{(x+h)}-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h-\frac{h}{x(x+h)}}{h}$

$=lim_{h\rightarrow 0}\frac{h(1-\frac{1}{x(x+h)})}{h}$

$=lim_{h\rightarrow 0}1-\frac{1}{x(x+h)}$

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I hope it helps you!

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