The area of any circle is equal to
, where r is the radius.
We know that the diameter is 12. The radius is always half of the diameter, so the radius of our circle must be 6.
Substitute 6 for r in our equation and simplify.
π6² = π6×6 =
36π in²
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76
Answer:
Step-by-step explanation:
24/3 - 4
8 - 4 = 4
Answer:
see explanation
Step-by-step explanation:
Given the 3 equations
3x + 5y + 5z = 1 → (1)
x - 2y = 5 → (2)
2x + 4y = 11 → (3)
Use (2) and (3) to solve for x and y
Multiply (2) by 2
2x - 4y = 10 → (4)
Add (3) and (4) term by term
4x = 21 ( divide both sides by 4 )
x = 
Substitute this value of x into (3)
2 × + 4y = 11
+ 4y = 11 ( subtract from both sides )
4y = 
( divide both sides by 4 )
y = 
Substitute the values of x and y into (1) and solve for z
3 × + 5 × + 5z = 1
+ 
+ 5z = 1
+ 5z = 1 ( subtract from both sides )
5z = - 
( divide both sides by 5 )
z = - 
Solution is
x = , y = , z = -
