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never [62]
2 years ago
7

Find the sine ratio for ∠D. a. 7/25 b. 24/7 c. 25/24 d. 24/25

Mathematics
1 answer:
Shalnov [3]2 years ago
8 0

Answer:

sin ∠D = 24/25

Step-by-step explanation:

sin = opposite / hypotenuse

Looking at ∠D, the opposite side is 24, hypotenuse is 25

Therefore sin = 24/25

You might be interested in
How do you solve for x
larisa [96]
Well, <T+<S will equal 11x +2 
so the equation will be 5x+10 + 58 = 11x +2
5x + 68 = 11x +2
66 = 6x (subtract 2, subtract 5x)
x = 11 (division)

To check,
<T = 5 (11) +10
<T = 65
11(11)+2 = 123
<T+<S = 123
65+58 = 123



8 0
3 years ago
Please help me ☣️☢️☢️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️▫️​
svet-max [94.6K]

Answer:

(a) 27 degrees (nearest degree)

(b) 17.9 m  (to one decimal place)

Step-by-step explanation:

Wow, that's along ladder, perhaps for the firemen!

From diagram,

(a)

sin(x) = 9 / 20 = 0.45

x = arcsin(0.45) = 26.74 degrees

(b)

height of wall ladder reaches

h = 20*cos(x) = 20*cos(26.74) = 17.86 m

8 0
3 years ago
How do you graph y=8.5x
vladimir1956 [14]

Answer:

You graph in the middle of the box

Step-by-step explanation:

go up 8 and to the right of box half way in the middle

8 0
2 years ago
Fill in the missing expression
padilas [110]

Answer:

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]          +     [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +    [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0   ]    =   [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [         ]   +      [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>1. First row:</u>

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

[      ] = [10a+ 3]  - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

<u>2. Second colum:</u>

[ a + 3 ] + [ 4 + a ] + [       ] =  [ 3a + 8 ]

[        ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a  + a  + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>3. Complete the row 3:</u>

<u></u>

     [      ]   +   [ a + 1 ]   +      [  -3a  ]  =   [     1      ]

    [      ]   =    [     1      ]   -   [ a + 1 ]   -    [  -3a  ]  = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>4. Complete the fourth column:</u>

[ 10a + 3 ] + [    ] + [   1   ] = [10a + 2b + 8 ]

[    ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>5. Complete the second row:</u>

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

 [      ]   =   [  2b + 4 ] - [ 2b ]  -   [ 4 + a ]  = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ]  +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                +                    +                    +

[ 2b ]  +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +               +                     +                    +

[   2a   ]   +   [ a + 1 ]   +   [  -3a  ]  =   [     1      ]

  =               =                    =                   =

[      ]  +   [ 3a + 8 ]  +     [         ]    =   [10a + 2b + 8 ]

<u>6. Complete the first colum:</u>

[ 5a ] + [ 2b ] + [2a ] = [   ]

[   ] = [ 7a + 2b ]

So far:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                    =

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

<u>7. Complete the last row:</u>

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

[         ]    =   [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +     [ -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0  ]     =   [10a + 2b + 8 ]

5 0
3 years ago
In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
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