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3 years ago

What is 17÷7? Can it be done?

1 answer:

8 0

If you divide using long division,yes it can!

7 can only be found in 17 two times,which equals 14. And 17-14 = 3. So,the answer is 2 with a remainder of 3.

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Help plzzz!!! Find a a= 12 a= 10 a= 1 a= 29

RideAnS [48]

Answer:

a=22.6549

Step-by-step explanation:

Calculated based on 2 given angles and 1 given side.

∠C = 180° - A - B = 0.99484 rad = 57°

a = c·sin(A)/sin(C) = 22.6549

b = c·sin(B)/sin(C) = 12.33874

3 0

2 years ago

Translate the figure 3 units left and 4 units down.

stellarik [79]

Answer:

3,-1

Step-by-step explanation:

you go over to the left 3 and than you go down 4.

8 0

3 years ago

A bank charges a fee if your account balance falls below $50. Let b represent the account balance. Write an inequality to descri

Paraphin [41]

Answer:

b < 50. The solution has infinite solutions because any number smaller than 50 would work, and their are infinite numbers smaller than 50.

Step-by-step explanation:

3 0

3 years ago

Please help!!!!!!!! Find radius and diameter. will mark brainiest!!!!!!!!!!

mylen [45]

Answer:

The radius is given its 10 in

The diameter is 20 in

Step-by-step explanation:

Two find the diameter given the radius you just multiply by 2

10x2=20 therefore the diameter is 20

Hope this helps :)

8 0

2 years ago

Read 2 more answers

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago