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enyata [817]
3 years ago
15

A translation is applied to the square formed by the points A(−3, −4) , B(−3, 5) , C(6, 5) , and D(6, −4) . The image is the squ

are that has vertices ​ A′(−3, −6) ​, ​ B′(−3, 3) ​, C′(6, 3) and D′(6, −6) .
Select the phrase from the drop-down menu to correctly describe the translation.
The square was translated

A. 2 units down
B. 10 units down
C. 10 units to the left
D. 2 units to the left
Mathematics
2 answers:
likoan [24]3 years ago
4 0
All of the x values are the same so it is not moving left or right.
The y values are changing by being 2 less than the original. 
If you subtract 2 from each y value you get the new set of ordered pairs.
It is moving 2 units down 
Letter A
Pepsi [2]3 years ago
3 0
X-coordinate is fixed. SO no left or right motion

Y coordinates are 2 less.
So It is moving 2 units down
Answer is A
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Step-by-step explanation:

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3 years ago
Will give brainliest, please help fast​
Gekata [30.6K]

Answer:

Converting the equation x^2-20x+13=0 into completing the square method we get: \mathbf{(x-10)^2=87}

Step-by-step explanation:

we are given quadratic equation: x^2-20x+13=0

And we need to convert it into completing the square method.

Completing the square method is of form: a^2-2ab+b^2=(a-b)^2

Looking at the given equation x^2-20x+13=0

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as:  2(x)(10)

So, we need to add and subtract (10)^2 on both sides

x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87

So, converting the equation x^2-20x+13=0 into completing the square method we get: \mathbf{(x-10)^2=87}

4 0
3 years ago
Compare 4 x 105 and 5 x 103.
german
Your answer should be B !
6 0
3 years ago
1-22 teacher was no help
damaskus [11]
1) 1,2,3,4,5,6,7
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3 0
3 years ago
Compare adding unlike fractions and adding like fractions
muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : \frac{1}{4} +\frac{2}{4}=\frac{1+2}{4}  =\frac{3}{4}

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

\frac{1}{5}+\frac{3}{4}

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}

4 0
3 years ago
Read 2 more answers
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