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Irina18 [472]
3 years ago
14

How do you solve the literal equation y=4/5x-9?

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

todays my birthday

Step-by-step explanation:

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which measure of central tendancy is found by calculating the sum of all data in the set divided by the number of data values in
Ilia_Sergeevich [38]
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The median is the middle value in the list of data values.
The mode is the value which occurs most often.
</span><span>The interquartile range is the difference between the third and the first quartiles.</span>
5 0
3 years ago
SOMEONE PLEASE HELP ME ON QUESTION 14!!
LUCKY_DIMON [66]

Answer:

WHere?? Wdymmm?

Step-by-step explanation:

5 0
3 years ago
Answer the problem and show all work.
marishachu [46]

Member Price = 30 + 3x

Non-member Price = 6x

x = the tickets they buy.

We want 30 + 3x = 6x

So, first we subtract 3x from each side and are left with:

30 = 3x

Then, divide each side by 3.

10 = x

So, the cost of 10 tickets is the same more non-members and members.

We can also check it:

Member Price: 30 + 3(10)

30 + 30 = 60

Non-member Price: 6(10)

60

8 0
2 years ago
A campus has 55% male students. Suppose 30% of the male students pick basketball as their favorite sports compared to 20% for fe
krok68 [10]
This is question of probability finding using bayes theorem  
It is used to calculate probability of two competing statements 
now p(m) = .55 
p(~m)= .45 
now for basketball for male  
p(b|m)=.30
 and for female 
p(b|~m)=.20 
so by bayes theorem  
p(m|b)=p(b|m)*p(m)/(p(b|m)*p(m)+p(b|~m)*p(~m)) 
so answer is E 
(.55)(.30) / (.55)(.30) + (.45)(.20)
7 0
3 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
1 year ago
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