Ask question

Ask question

All categories

3 years ago

14

How do you solve the literal equation y=4/5x-9?

1 answer:

Wewaii [24]3 years ago

3 0

Answer:

todays my birthday

Step-by-step explanation:

You might be interested in

olchik [2.2K]

A. The cost of buying x number of concert tickets for $76 each.

3 0

3 years ago

How to multiply numbers with exponets and different bases

o-na [289]

When the bases are diffenrent and the exponents of a and b are the same, we can multiply a and b first:
a n ⋅ b n = (a ⋅ b) n
Example:
32 ⋅ 42 = (3⋅4)2 = 122 = 12⋅12 = 144

When the bases and the exponents are different we have to calculate each exponent and then multiply:
a n ⋅ b m
Example:
32 ⋅ 43 = 9 ⋅ 64 = 576

5 0

3 years ago

Write the ratio 36 computers for every 6 students in 3 ways

rjkz [21]

Answer:

Step-by-step explanation:

Lol

6 0

3 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

Answer this equation: 4 3/5 - -3 2/5 + 3

horrorfan [7]

Answer:

24

Step-by-step explanation:

$4\frac{3}{5} -(-3\frac{2}{5})+3$

Negative and another negative makes a positive.

$4\frac{3}{5}+3\frac{2}{5}+3$

Add the fractions first.

$7\frac{5}{5}+3$

5/5 is equivalent to 1. 7 5/5 becomes 8.

$8+3$

Add the numbers.

$24$

I hope this helps!

6 0

3 years ago

Read 2 more answers