The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²
We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²
This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x
The area,
88 = (20 - 2x)(14 - 2x)
Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²
Divide the equation by 4,
22 = 70 - 17x + x²
Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.
Thus, the thickenss is equal to 58.2 in
Answer:
c=54
Step-by-step explanation:
c/6=9
6/1 ·c/6=9·6
c= 54
Suppose we choose

and

. Then

Now suppose we choose

such that

where we pick the solution for this system such that

. Then we find

Note that you can always find a solution to the system above that satisfies

as long as

. What this means is that you can always find the value of

as a (constant) function of

.
Answer:

Step-by-step explanation:
We have the quadratic equation
i.e. 
As, the roots of the quadratic equation
are given by
.
So, from the given equation, we have,
a = 1, b = -36 , c = -324.
Substituting the values in
, we get,

i.e. 
i.e. 
i.e. 
i.e.
and 
i.e.
and 
i.e. x = 43.45 and x = -7.45
Thus, the roots of the equation are 43.45 and -7.45.
Hence, the factored form of the given expression will be 
Answer:
The probability of not spinning a 5, flipping heads, then spinning a 1 is 0.08
Step-by-step explanation:
I may assume the spin contains 5 numbers ( plz change and recalculate if the no. of numbers is different)
P(not spinning a 5) = 4/5
P(flipping head) = 1/2
P(spinning 1) = 1/5
P(not spinning a 5, flipping heads, then spinning a 1)= 4/5 * 1/2 * 1/5 = 0.08 = 0.1