1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VARVARA [1.3K]
3 years ago
15

1.27 reapeating as a fraction

Mathematics
1 answer:
Ahat [919]3 years ago
4 0
1.27 = 1 27/100
I hope this helps!
You might be interested in
If the point (x, -2) is a solution to the equation y = 2x – 4, find the value of x.
guapka [62]
This should your answer:

X = 4

7 0
3 years ago
Read 2 more answers
The Venn diagram shows event A and event B comprised of outcomes from the same sample space. The probability of event A is given
Masteriza [31]

Answer:

The probability of an event is a number describing the chance that the event will happen. An event that is certain to happen has a probability of 1. An event that cannot possibly happen has a probability of zero. If there is a chance that an event will happen, then its probability is between zero and 1

A=45

Step-by-step explanation:

7 0
4 years ago
the athletic department spent $11,250 on the 15 sports at the school. what is the rate that the athletic department spent in eac
Sholpan [36]

Answer:

$11,250 divided by 15 is 750, which means that the answer is the rate is $750 dollars spent in each sport.

5 0
3 years ago
Read 2 more answers
what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4
eduard

For this case we have the following expression:

2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})

Rewriting the numbers within the roots we have:

2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})

Then, by properties of powers we have:

2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})

Then, by radical properties we have:

2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})

Rewriting the expression we have:

4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}

Finally, adding similar terms we have:

(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}

13\sqrt[4]{x}-10\sqrt[4]{2y}

Answer:

The simplified form of the expression is:

13\sqrt[4]{x}-10\sqrt[4]{2y}

7 0
3 years ago
Read 2 more answers
Please help with these two questions​
nevsk [136]

Answer:

10. Let m<Y = y.

Then,

m<Y + m<X +m<Z = 180 [ Sum of angles of triangle is 180 degrees]

or, y + (6x-23) + (4x + 9) = 180

or, y + 10x -14 = 180

or, y = 194 - 10x

or, m<Y = 194 - 10x

12. Solution,

a.  m<1 = 60 degrees [Each angles of equilateral triangle is equal to 60 degrees]

b.  In triangle WYZ,

m<Z + m<ZWY + m<ZYW =180 [Sum of angles of triangle is 180]

or, 138 + m<ZWY +m<ZWY =180 [Base angles of isosceles triangle are equal, i.e. m<ZYW = m <ZWY]

or, 2 (m<ZWY) = 180 -138 = 42

or, m<ZWY = 21 = m<ZYW

or, m<3 = 21 = m<5

c. Solution,

m<XWY = m<2 + m<3 [Addition axiom]

or, 60 = m<2 + 21 [Each angle of equilateral triangle is 60]

or, m<2 = 39

d. Solution,

m<4 + m<5 =60 [<XYW = 60 ]

or, m<4 + 21 = 60

or, m<4 = 39

7 0
3 years ago
Other questions:
  • The__________ method is a way of solving a system of equations using addition or subtraction to eliminate a variable.
    6·1 answer
  • Find two consecutive numbers whose square differ by 25
    5·1 answer
  • Reasoning Zach texted 8 different friends each day for three days about a new game. Then Zach texted 8 friends about a new movie
    5·1 answer
  • I need help my question is 4/7 divided by -13/5
    8·2 answers
  • R^2 = 4r-4<br><br> Please show steps
    7·1 answer
  • Please help!!!! question 5/5
    9·2 answers
  • What is the y-intercept of the graph of the function f(x)=x^2+3x+5?
    15·2 answers
  • I'm thinking of a two digit number.
    11·2 answers
  • The table shows how the number of pepperoni
    13·1 answer
  • Somebody please help me !!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!