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grin007 [14]
3 years ago
15

Write the equation of the quadratic equation function i standard form represented by the graph

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

x^{2} +6x+8=0

Step-by-step explanation:

we know that

The quadratic equation in standard form is equal to

ax^{2} +bx+c=0

In this problem we have

the vertex is equal to the point (-3,-1)

The zeros of the function are the points (-4,0) and (-2,0)

The graph of the figure is a vertical parabola open upward

the equation of a vertical parabola in vertex form is equal to

y=a(x-h)^{2}+k

where (h,k) is the vertex of the parabola

substitute

y=a(x+3)^{2}-1

with the point (-2,0) find the value of a

0=a(-2+3)^{2}-1

0=a(1)^{2}-1

a=1

the equation in vertex form is equal to

y=(x+3)^{2}-1

Convert to standard form

y=x^{2} +6x+9-1

equate to zero

x^{2} +6x+9-1=0

x^{2} +6x+8=0

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