Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs are solutions to the equation
Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.
(- 1, - 6)
3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution
(- 3, 3)
3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution
(11, 3)
3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution
(7, 0)
3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution
The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation
Here is the set up:
(1/4)/2 = (9/4)/y
Solve for y.
First you need to divide 64 by 75 and then multiply by 100 which is 85.3% which then you need to find the average of the 2 which will be (85.3+x)/2=88 where x= the value of the second test.
Then you will need to isolate the x with the following steps:
- multiply each side by 2 making it 85.3+x=176
- Subtract 85.3 from each side
- this results in 90.7
