VERY REGENT PLEASE HELP

Maru [420]

Answer:

1. -3 2. 3

Step-by-step explanation:

Evaluate each expression is very simple concept in math. When you substitute a particular value for each variable and then act the operations called evaluating expression.

8 0

3 years ago

Read 2 more answers

I need help with #39-42, please explain.

shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

$l=m\sqrt{n}$

Question 39:

When ' n ' increase, the $\sqrt{n}$ will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As $n$ increases and $m$ stays constant , $l$ increases

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Question 40:

Solving the equation for m, we get

$l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}$

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As $l$ increase and $n$ stays constant, $m$ increases

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For question 41 & 42, we need to use the below equation to complete the sentence

$r=s^2/t^2$

Question 41:

When $s$ is triped, the equation will be...

$r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2} =9s^2/t^2$

Solution for question 41:

If $s$ is tripled and $t$ stays constant, $r$ is multiplied by 9

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Question 42:

When t is doubled, the equation will be...

$r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\ \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}$

Solution for 42:

If $t$ doubled and $s$ stays constant, $r$ is multiplied by 1/4 or 0.25

3 0

2 years ago

in a park, a bike path and a horse riding path are parallel. In one part of the park a hiking trail intersects the two paths. Fi

tatuchka [14]

Answer:

angle one

Step-by-step explanation:

4 0

3 years ago

the length of an arc of a circle is 1/5 of its circumference. if the area of the circle is346.5cm²,find the angle subtended by t

dexar [7]

Answer:

72°

Step-by-step explanation:

From the question,

Area of the circle = πr²

A = πr²................. Equation 1

Where r = radius of the circle.

⇒ r = √(A/π)............. Equation 2

Given: A = 346.5 cm², π = 3.14

r = √(346.5/3.14)

r = √(110.35)

r = 10.5 cm.

Therefore,

circumference of the circle = 2πr = 2×3.14×10.5

circumference = 65.94 m

If the length of the arc(s) is 1/5 of its circumference.

Therefore, length of arc (s) = 13.188

⇒ length of arc/circumference = 13.188/65.94 = 1/5

s/2πr = θ/360

Where θ = angle substends at the center of the circle

1/5 = θ/360

θ = 360/5

θ = 72°

3 0

2 years ago

Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.

klasskru [66]

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

x^2+3x-70=0

(x-7)(x+10)=0

x-7=0

x+10=0

x=7

x=-10

AB=x+5

AB=12

AB=-5

BC=x-2

BC=5

BC=-12

Area of ABC = 30cm2

Perimeter of ABC = AB+BC+AC

8 0

2 years ago