The answer would be p= -2
To check it:
-2(5(-2) - 3) = 26
-2(-10-3) = 26
-2(-13) = 26
26 = 26
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
The dependent variable is y, that represents the years
Answer:
Step-by-step explanation:
Find the slope, denoted m
This is done by using the formula m = (y2 - y1)/(x2 - x1)
The slope for this problem is
m = [-3 - (-1)]/[8 - (-2)]
m = -2/10 = -1/5
