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Sveta_85 [38]
3 years ago
5

Find two consecutive integers whose sum is 67. Which of the following equations could be used to solve the problem? 2x = 67 2x +

1 = 67 2x + 2 = 67 x2 + 1= 67
Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

Let

x--------> the first consecutive integer

x+1-----> the second consecutive integer

we know that

x+(x+1)=67\\2x+1=67

therefore

<u>the answer is</u>

2x+1=67

Delvig [45]3 years ago
8 0
X + (x+1) = 67 
<span>^ ^ Integer 2 </span>
<span>Integer 1 </span>

<span>By simplifying, we get 2x + 1 = 67. Therefore, either "2x + 1 = 67" or "x2 + 1= 67" can be used. </span>

<span>Your answer by solving for 'x' would be: </span>

<span>2x=66 </span>
<span>x=33 </span>
<span>Therefore, (x+1)=34 </span>

<span>Hence, the 2 consecutive integers are 33 and 34. When added together, they equal 67, and they are consecutive (34 is 1 larger than 33). </span>
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Step-by-step explanation:

We know the following info:

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We want to find a confidence interval for the difference of means and the correct formula to do this is:

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(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

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