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Fudgin [204]
3 years ago
7

Positionx (m)

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

(y : position and x : time)

Let y1 = 2m and y2 = 14m,

t1 = 0s and t2 = 4s

v = (14 - 2)m/(4-0)s

= 12m/4s

= 3.0 m/s

9966 [12]3 years ago
6 0

Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

v =  \frac{y1 - y2}{x1 - x2}

(y : position and x : time)

Let y1 = 2m and y2 = 14m,

t1 = 0s and t2 = 4s

v = (14 - 2)m/(4-0)s

= 12m/4s

= 3.0 m/s

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4 years ago
Sara invests $1,200 each year in an IRA ( 12 years in an account that earned 5%
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A)

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\

\bf \begin{cases}
A=
\begin{array}{llll}
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\end{array}
\begin{array}{llll}

\end{array}\\
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\begin{array}{llll}
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t=years\to &12
\end{cases}

B)

let's say after 12years, she ended up with a value of say "P"
so.. now she's just sitting on P, making no more deposits to it
just taking whatever the compound 5% interest will give, thus

\bf \qquad \textit{Compound Interest Earned Amount}
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A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
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P=\textit{original amount deposited}\to &\boxed{P}\\
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\begin{array}{llll}
\textit{times it compounds per year}\\
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t=years\to &11
\end{cases}


C)

from A) she made 1,200 every year, for 12 years that's 1200*12, that's how much she put out of pocket, if you got an amount P from A), then the interest is just the difference, or P - (1200*12)

from B), she started with an original amount of P, and ended up with a compounded amount of A after 11years, so the interest is just also the difference, or A - P

add those two folks together, and that's the total interest she got for the 23  years



4 0
4 years ago
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note that for this problem i was working backwards which is a very powerful problem solving tool: start with what you want to attain, and then see how you can go from where you are now to get to your destination.

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