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Alex73 [517]
3 years ago
11

Explain why there must be at least two lines on any given plane

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0
BECAUSE THERE IS A Y AXIS AND AN X AXIS THOSE R THE 2 GIVIN LINES
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Stuck on this question. May I please have some help?
Rina8888 [55]

Answer:

So a point is (-3,-5) and the vertex is (-4,-3)

Step-by-step explanation:

This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.

The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)

I will choice -3.  This gives -2(-3+4)^2-3

f(-3)=-2(1)^2-3

f(-3)=-2-3

f(-3)=-5

So a point is (-3,-5) and the vertex is (-4,-3)

4 0
3 years ago
Read 2 more answers
A survey found that 12 out of every 15 people in the United States prefer eating at a restaurant over cooking at home. if 400 pe
Snezhnost [94]

12x  = 400

x = \frac{400}{12}

15x = 15 * \frac{400}{12}

x = 500.

∴ 500 people took the survey

5 0
3 years ago
Read 2 more answers
Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36
Vladimir79 [104]

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

If you want to learn more about intersection points:

brainly.com/question/17206319

#SPJ1

5 0
2 years ago
Given a right triangle with legs a, b and hypotenuse c, solve for b if a= 72 and c= 75
kotykmax [81]

Answer:

The answer is a. 21.

Step-by-step explanation:

We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.

Here,

Hypotenuse of the given triangle(c)=75

Two sides of right angled triangle are:

a=72

b=?

Then,

for a given right angled triangle abc,

Using Pythagoras theorem,

c=\sqrt{a^{2} +b^{2} }

Squaring on both sides,

c^{2} =a^{2}+b^{2}

or,75^{2}=72^{2}+b^{2}

or, b^{2}=75^{2}-72^{2}

or,b^{2}=5625- 5184

or,b^{2} =441

∴b=21

So, the value of b is obtained to 21 by the use of Pythagoras theorem.

7 0
3 years ago
IXL geometry please help!
Sedaia [141]
<h3>Answer: 32 degrees</h3>

================================

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc ABC = 2*(angle D)

arc ABC = 2*(35)

arc ABC = 70 degrees

-------------

break arc ABC into its smaller pieces

(minor arc AB)+(minor arc BC) = arc ABC

(38)+(minor arc BC) = 70

minor arc BC = 70-38

minor arc BC = 32

8 0
3 years ago
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