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Lerok [7]
3 years ago
13

Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

Mathematics
2 answers:
Elanso [62]3 years ago
8 0
 5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
 (1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).
Step by step solution :Step  1  :Equation at the end of step  1  :  (((5 • (x3)) -  22x2) -  20x) +  16  = 0  Step  2  :Equation at the end of step  2  :  ((5x3 -  22x2) -  20x) +  16  = 0 Step  3  :Checking for a perfect cube : 3.1    5x3-4x2-20x+16  is not a perfect cube 
Trying to factor by pulling out : 3.2      Factoring:  5x3-4x2-20x+16 
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1:  5x3+16 Group 2:  -4x2-20x 
Pull out from each group separately :
Group 1:   (5x3+16) • (1)Group 2:   (x+5) • (-4x)


I hope it helps
Lera25 [3.4K]3 years ago
7 0

Answer:

(5x-4)(x^2+4)

Step-by-step explanation:

Consider the given expression

5x^3-4x^2+20x-16

We need to find the factor form of given expression.

Using grouping method we get

(5x^3-4x^2)+(20x-16)

Taking out highest common factors from each group.

x^2(5x-4)+4(5x-4)

Taking out common factors.

(5x-4)(x^2+4)

Therefore, the factored form of given expression is (5x-4)(x^2+4).

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2. To confirm the equations to be equal with the parent function we do as follows:
<span> (2x – 4)(x + 5) = 2x^2 + 10x - 4x - 20 = 2x^2 + 6x -20
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What are the solution(s) for the quadratic equation?<br><br> Y=5x^2-9x+4<br><br> Show work
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Let's see

\\ \rm\rightarrowtail 5x^2-9x+4=0

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