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4 years ago

Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

2 answers:

8 0

5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)

I hope it helps

Lera25 [3.4K]4 years ago

7 0

Answer:

$(5x-4)(x^2+4)$

Step-by-step explanation:

Consider the given expression

$5x^3-4x^2+20x-16$

We need to find the factor form of given expression.

Using grouping method we get

$(5x^3-4x^2)+(20x-16)$

Taking out highest common factors from each group.

$x^2(5x-4)+4(5x-4)$

Taking out common factors.

$(5x-4)(x^2+4)$

Therefore, the factored form of given expression is $(5x-4)(x^2+4)$ .

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2x=-y in standard form

IgorC [24]

Answer:

y=-2x

Step-by-step explanation:

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3 years ago

Two numbers have a sum of 20 and a difference of 16 what are the two numbers

HACTEHA [7]

A. 18+2 = 20 abs 18-2= 17

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3 years ago

6 (3x-1)-10x. with work please :)

STatiana [176]

Hey there!
Let's break this expression into two parts:
6(3x-1) and -10x

To solve the first part, we need to use the distributive property which states:
a(b+c) = ab+ac

Applying that to this problem, we have:
6(3x) + 6(-1) =
18x - 6

Now, we can take that -10x and put it right back in:

18x - 6 - 10x

Combine like terms and subtract the 10x from the 18x to get:
8x - 6

Hope this helps!

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3 years ago

Find sin(α) in the triangle.

cluponka [151]

$\frac{20}{29}$ Answer:

sin α = $\frac{20}{29}$

Step-by-step explanation:

sin α = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{20}{29}$

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2 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago