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3 years ago

14

Antwan’s car loan is automatically deducting $150 from his bank account every month. How much will the deductions total for the

year?

1 answer:

KiRa [710]3 years ago

4 0

Answer:

$1,700

Step-by-step explanation:

Multiply the rate that money is being taken out at by the amount taken out at

12 x 150

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Joes, who is the youngest member of the wrestling team at Northwood High school, is 5 years less than one-half the age of the co

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1/2 n - 5 or (n/2) - 5

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3 years ago

NO LINKS WILL MARK BRAINLIEST

professor190 [17]

Answer:

30.2 sq cm

Step-by-step explanation:

bass times height 10 cm bottom and 3.2 height

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3 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

3 years ago

Allison is rolling her hula hoop on the playground. The radius of her hula hoop is 35 cm. What is the distance the hula hoop rol

lidiya [134]

Answer:

Distance covered by hula hoop rolls in 4 full rotations is 880 cm .

Step-by-step explanation:

Formula

$Perimeter\ of\ a\ circle = 2\pi r$

Where r is the radius of the circle.

As given

Allison is rolling her hula hoop on the playground.

The radius of her hula hoop is 35 cm.

r = 35 cm

$\pi = \frac{22}{7}$

Putting the value in the formula

$Perimeter\ of\ a\ hula hoop = 2\times \frac{22}{7} \times 35$

= 220 cm

As given

The hula hoop rolls in 4 full rotations.

Distance covered by hula hoop rolls in 4 full rotations = 220 × 4

= 880 cm

Therefore the Distance covered by hula hoop rolls in 4 full rotations is 880 cm .

6 0

3 years ago

Convert 11 milliliters to fluid ounces. Use 1 mL ≈ 0.034 fl oz.

VladimirAG [237]

Answer:

0.371954

Step-by-step explanation:

Formula- for an approximate result, divide the volume value by 29.574.

3 0

3 years ago

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