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prisoha [69]
3 years ago
5

Select all of the quadrants that the parabola whose equation is y2= X-4 (principal square root) occupies.​

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0

Answer:

Quadrants I and IV

Step-by-step explanation:

When we graph y^2 = x - 4, we see that it is on the x axis, and goes up into Quadrant I, and down into Quadrant IV

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Pleaseee helpppp:)))
matrenka [14]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

=  \frac{42}{75}

<em><u>Therefore</u></em><em><u>, </u></em>

Out of 200 families, no. of families had cars

= 200 \times  \frac{42}{75}

=200 \times   \frac{14}{25}

= 8 × 14

= 112

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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3 years ago
Find the 52nd term for the following sequence. 16,6,-4,-14....
nikklg [1K]
I think it’s D, sorry if I’m wrong.
8 0
3 years ago
(01.02)
Bas_tet [7]

Step-by-step explanation:

it is option c. you interchange the value with y and take inverse.

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3 years ago
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Vera_Pavlovna [14]
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6 0
3 years ago
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Please solve the table and show your work
Elanso [62]

Answer:

a

Step-by-step explanation:

3 0
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