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Marina CMI [18]
3 years ago
8

Find the slope of line containing the given points. (3,-8),(1,4)​

Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer:

m = -6

Step-by-step explanation:

As we move from point (1,4)​ to point (3,-8)​, x increases by 2 and y decreases by 12.  Thus, the slope of this line is m = rise / run = -12/2 = -6.

iris [78.8K]3 years ago
3 0

Answer: ⁻6 is your answer.

Step-by-step explanation:

To find the slope use the slope equation: m=y₁-y₂/x₁-x₂

Sub: m= ⁻8-4/3-1

Solve: m= ⁻12/2

Sam: m= ⁻6/1 or -6

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Help, I’ll give brainliest and thanks
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(05.01 MC) In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of on
REY [17]

Answer:

sin(b^\circ) = \dfrac{3}{5}

Step-by-step explanation:

We are given a \triangle JKL where \angle K = 90^\circ

tan(b^\circ) = \dfrac{3}{4}\\cos(b^\circ) = \dfrac{4}{5}

As per trigonometric rules,

tan(\theta) = \dfrac{Perpendicular}{Base}

cos(\theta) = \dfrac{Base}{Hypotenuse}

Comparing the given value of tangent and cosine:

Perpendicular = 3 units

Base = 4 units

Hypotenuse = 5 units

Also, we know that:

sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin(b^\circ) = \dfrac{3}{5}

Now, it is given that the triangle is dilated by a scale factor of \frac{1}{2}.

i.e. all the sides will become half of its initial values.

New Perpendicular = 1.5 units

New Base = 2 units

New Hypotenuse = 2.5 units

Using the formula for sine:

sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow  sin(b^\circ)= \dfrac{1.5}{2.5}\\\Rightarrow  sin(b^\circ)= \dfrac{15}{25}\\\Rightarrow   sin(b^\circ)=\dfrac{3}{5}

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3 years ago
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Answer:

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So, Joseph receives $16 per week.

Step-by-step explanation:

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3 years ago
The LCD of two fractions is the same as the LCM of the numerators of the fractions.
N76 [4]
That is actually false. The LCD of two fractions is the same as the LCM of the denominators, not numerators :) Hope this helped!
4 0
3 years ago
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