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Vladimir79 [104]
3 years ago
8

Negative 3 over 1 third plus 8 over 3 tenths

Mathematics
1 answer:
Katen [24]3 years ago
3 0

The answer to your question is 7/5

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Use the normal distribution of fish lengths for which the mean is 11 inches and the standard deviation is 2 inches. assume the v
Kaylis [27]

To solve this problem, we make use of the z statistic. What we have to do here is to find for the z score using the given data and from the standard probability tables for z, we locate the proportion of the fish longer than 12 inches.

 

The formula for calculating the z score is:

z = (x – μ) / σ

where,

x = the sample value = 12 inches

μ = the sample mean = 11 inches

σ = 2 inches

 

so,

z = (12 – 11) / 2

z = 1 / 2

z = 0.5

 

Since we are looking for the values greater than 12, so this is a right tailed test. Using the tables, the value of p at this value of z is:

p (z = 0.5) = 0.3085

 

Therefore there is a 30.85% probability that the fish is longer than 12 inches.

3 0
3 years ago
The 1st term in a geometric series is 5 and the common ratio is 2. Find the sum of the 1st 10 terms in the series.
lesya [120]

Answer:

5115

Step-by-step explanation:

a1(1-(r)^n)/1-r

5(1-(2.00)^10)/1-2.00

3 0
3 years ago
Write the sentence as an equation.<br> c is 256 subtracted from g
romanna [79]

Answer:

c = g - 256

Step-by-step explanation:

The word "is" indicates an equal sign, and saying you take 256 from g is g - 256.

3 0
3 years ago
This is a map of three towns. It shows the train line and the highway that connects the towns. The north direction is shown. The
vlada-n [284]

Answer:

  about 106 km

Step-by-step explanation:

The distance between the two towns can be estimated several ways. In the attachment, we chose to measure the angles on the map. Using the law of sines, we can estimate the unknown distance.

The distance can also be estimated using the Tounouse-Avaria distance as a ruler. For best results, that ruler would need to be subdivided to an appropriate level.

__

<h3>angle measures</h3>

The angles in the triangle can be measured using a protractor or some other tool. The attachment shows the results from a geometry program:

  • ∠TMA ≈ 107°
  • ∠TAM ≈ 24°
<h3>law of sines</h3>

The law of sines tells us the distances are proportional to the sines of the opposite angles:

  TM/sin(TAM) = TA/sin(TMA)

  TM = sin(24°)×(250 km)/sin(107°) ≈ 106.3 km

The distance from Tounouse to Mt. Monotti is estimated to be about 106 km.

__

<em>Alternate solution</em>

Using a compass or dividers to project the TM distance onto TA, we find it is between 0.4 and 0.5 of the TA distance. The difference between 2×TM and TA can be estimated to be about 0.4×TM. That is, ...

  TM ≈ TA/2.4 ≈ (250 km)/2.4 ≈ 104.2 km

This estimate is consistent with the one found using angle measures.

4 0
2 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
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