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3 years ago

Please help! I'll mark you brainliest :D

Mathematics

1 answer:

Grace [21]3 years ago

5 0

Answer:

range: -3<x<7

Step-by-step explanation:

The curve of this function starts at x=-3 and ends at x=7, so this function's range is : -3<x<7

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In the diagram, AE = 2AC and ∠BAC ≅ ∠DAE. What additional information is necessary to prove that ΔABC is similar to ΔADE, using

ss7ja [257]

Since you want to use the SAS theorem, you must find sides that are either side of angles BAC and DAE. You have already made use of sides AE and AC, so the other sides you need to choose are AB and AD. The appropriate relationship for similarity is ...

... AD = 2AB

since you want the sides of triangle ADE to be twice then length of those in triangle ABC.

7 0

3 years ago

Read 2 more answers

Kelly price sells college textbooks on commission. She gets 8 % on the first $7500 of sales, 16% on the next $7500 of sales, a

Solnce55 [7]

Answer:

The commission would be $ 920.

Step-by-step explanation:

Given,

Sales in 1997 = $ 9500,

Since, there is a commision of 8 % on the first $ 7500 of sales, 16% on the next $ 7500 of sales, and 20% on sales over $ 15,000,

If x represents the total sales,

Commission for x ≤ 7500 = 8% of x = 0.08x,

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of (x-7500)

= 600 + 0.16(x-7500),

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of 7500 + 20% of (x-15000)

= 600 + 1200 + 0.20(x-15000)

= 1800 + 0.20(x-15000)

Thus, the function that shows the given situation,

$f(x)=\left\{\begin{matrix}0.08x & x \leq 7500\\ 600+0.16(x-7500) & 7500 < x \leq 15000\\ 1800+0.20(x-15000) & 15000 < x\end{matrix}\right.$

Since, 9500 lies between 7500 and 15000,

Therefore, the commission would be,

f(9500)= 600 + 0.16(9500 - 7500) = 600 + 320 = $ 920

7 0

3 years ago

Simplify by distributing<br> 7(36 – 2c + 4)

Nostrana [21]

Step-by-step explanation:

7(36-2c+4)

=252 - 14c + 28

=310 - 14c

7 0

3 years ago

Solve 3x2 + 4x = −5.

Alla [95]

Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
b=4
c=5

x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
x= $\frac{-4+/- 2\sqrt{-11} }{6}$
remember that√-1=i
x= $\frac{-4+/- 2i\sqrt{-11} }{6}$
x= $\frac{-2+/- i\sqrt{-11} }{3}$

x= $\frac{-2+ i\sqrt{-11} }{3}$ or x= $\frac{-2- i\sqrt{-11} }{3}$

4 0

3 years ago

Write an equation in slope-intercept form for a line that passes through the point (1, 6) and

Mars2501 [29]

Answer:

y=2x+4

Step-by-step explanation:

If the line has a slope of two, that means it goes up 2 on the y axis for every 1 on the x axis. So, if it goes through (1,6), then you can subtract 1 from the x axis and two from the y axis to find the y intercept, (0,4).

5 0

3 years ago