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3 years ago

Please help! I'll mark you brainliest :D

Mathematics

1 answer:

Grace [21]3 years ago

5 0

Answer:

range: -3<x<7

Step-by-step explanation:

The curve of this function starts at x=-3 and ends at x=7, so this function's range is : -3<x<7

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3(х + 3) 3х + 3 please help

shtirl [24]

I don’t really know but try a calculator

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3 years ago

If each Cube has edges 4 inch long what is the volume of the prism outlined in blue

melamori03 [73]

Answer:

3840 in^3

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3 years ago

Suppose that you can buy 5 apples for $2. How much would it cost to<br> buy 17 apples?

Doss [256]

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3 years ago

Read 2 more answers

The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).

Effectus [21]

Answer:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

Step-by-step explanation:

Given the quadratic equation as:

$2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0$

Let us put $sinx=y$ for simplicity of the equation:

Now, the equation becomes:

$2y^2+y-1=0$

Now, let us try to solve the quadratic equation:

$\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1$

So, the solution to the given trigonometric quadratic equation is:

$sinx = \dfrac{1}{2}$

and

$sinx=-1$

Let us try to find the values of $x$ in the interval $[0, 2\pi)$ .

$sin\theta$ can have a value equal to $\frac{1}{2}$ in 1st and 2nd quadrant.

So, $x$ can be

$30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}$

For $sinx=-1$ ,

$x = 270^\circ\ or\ \dfrac{3 \pi}{2}$

So, the answer is:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

7 0

3 years ago

The cost in dollars to print n books is 500 + 10n. How many books are printed for a cost of $15 000?

12345 [234]

N= the # of books
So you're trying to find n and you have the cost for the printed books, which is 15,000, so you would set up your equation like this:
15,000=500+10n
Subtract 500 from each side
14850=10n
Divide by 10
n=1,485 books are printed

8 0

3 years ago