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slega [8]
3 years ago
6

What’s the answer ???????????????????

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

f(9) = - 2/3

Step-by-step explanation:

I don't really know how to answer those but I think I am right

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10 times as many as blank tens is 30 tens
yKpoI14uk [10]
The answer to that question will be 3
8 0
3 years ago
M=7,r=8, t=2 ; mr/t = what
galina1969 [7]

Answer:

28

Step-by-step explanation:

Plug in the corresponding numbers to the corresponding variables. Note that:

m = 7

r = 8

t = 2

mr/t = (7 * 8)/2

(7 * (8/2)) = 7 * 4 = 28

28 is your answer.

~

4 0
3 years ago
How many times larger is the area of Rectangle 2 than the area of Rectangle 1?
aivan3 [116]

Answer:

I would need to see the rectangles and there areas to answer that sorry

8 0
3 years ago
Determine the most specific name for the figure in the diagram.
Makovka662 [10]
<span>ABCD is a parallelogram. Looking at the quadrilateral ABCD, the first thing to do is to determine if the opposite sides are parallel to each other. So let's check that by looking at the opposite sides. Line segment BA. When you go from point B to point A, you move to the right 1 space, and down 4 spaces. So the slope is -4. Looking at line segment CD, you also move to the right 1 space and down 4 spaces, which also means a slope of -4. So those two sides are parallel. When you compare line segments BC and AD, you'll notice that for both of them, you go to the right 5 spaces and up 2 spaces, so those too are parallel. So we can now saw that the quadrilateral ABCD is a parallelogram. Since ABCD is a parallelogram, we now need to check if it's a rectangle (we know it can't be a square since the sides aren't all the same length). An easy way to test if it's a rectangle is to check of one of the angles is 90 degrees. And if we draw a line from B to D, we can create a triangle ABD. And in a right triangle, due to Pythagora's theorem we know that A^2 + B^2 = C^2 where A is the line segment AB, B is the line segment AD and C is the line segment BD. So let's calculate A^2, B^2, and C^2. A^2: Line segment AB. We can construct a right triangle with A = 1 and B = 4. So C^2 = 1^2 + 4^2 = 1 + 16 = 17. So we have an A^2 value of 17 B^2: Line segment AD. We can construct a right triangle with A = 2 and B = 5. So C^2 = 2^2 + 5^2 = 4 + 25 = 29. So we have an B^2 value of 29 C^2: Line segment BD. We can construct a right triangle with A = 2 and B = 6. So C^2 = 2^2 + 6^2 = 4 + 36 = 40. So we have a C^2 value of 40. Now let's check if the equation A^2 + B^2 = C^2 is correct: 17 + 29 = 40 46 = 40 And since 46 isn't equal to 40, that means that ABCD can not be a rectangle. So it's just a parallelogram.</span>
6 0
3 years ago
A 20­ft ladder is leaning against a house. The bottom of the ladder is 3 ft from the house. To the nearest tenth of a foot, abou
Tasya [4]

Answer:  19.8 ft

Step-by-step explanation:

Use the Pythagorean Theorem formula to solve for how high the top of the ladder reach.  

The formula says  a^2 + b^2 = c^2

Where a and b are the two legs and  C is the hypotenuse.

In this situation, the hypotenuse will be length of the ladder , and either  a or b will be the length of the ladder from the building or the length of how long the ladder.

a will be 3 ,  and c will be 20. Input in the values  into the formula and solve for b.

3^2 + b^2 = 20^2

9 + b^2 = 400

-9              -9

 b^2 = 391  

    b = \sqrt{391}

  b  = 19.77371   round to the nearest tenth is ,  19.8

8 0
2 years ago
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