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photoshop1234 [79]
3 years ago
15

In which direction does the parabola y=4x^(2)-36 open?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
It opens up. hope this helps


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Maru [420]

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im too late

Step-by-step explanation:

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Evaluate the following question <br> PLZ
kozerog [31]

Answer:

1599995904

Step-by-step explanation:

first, you must do the top part of the fraction. you can start by doing the power numbers such as 2 power 4, 4 power 6 and 4 power 4.

the complete answer for the top part is: 12x 16x 4069x 8x 2x 256 which equals: 3199991808

then, you must divide by 2 which gives you the answer of: 1599995904

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Please, I need help ASAP! Which of the following shows the true solution to the logarithmic equation mc019-1.jpg
bekas [8.4K]
X = 1 is the correct answer.
Using the log properties, remember that Log(base2)2 = 1

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3 0
4 years ago
Choose the solutions to the two equation system.<br>6.0 + 3y = 30<br>15+ y = 7​
zloy xaker [14]

Answer:

y= -8 or 8

Step-by-step explanation

30-6= 24

24/3=8

y=8

15+y=7

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3 0
4 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
4 years ago
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