Question

(−2x^2+x+1)–(x^2–x+7)–(4x^2+2x+8) Please explain

Answer 1

Answer:

$-7x^2-14$

Step-by-step explanation:

First, remove the parenthesis.  Remember to distribute the negatives properly!

$(-2x^2+x+1)-(x^2-x+7)-(4x^2+2x+8)\\-2x^2+x+1-x^2+x-7-4x^2-2x-8$

Next, rearrange the order of the numbers so it's easy to see the like terms.  Put the squared x's together, x's together, etc.  This step is optional but helpful.

$-2x^2-x^2-4x^2+x+x-2x+1-7-8$

Next, combine like terms.

$-7x^2+0x-14\\-7x^2-14$

Leave a note in the comments if you need me to elaborate on any steps.