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prisoha [69]
3 years ago
7

WILL GIVE BRAINLIEST

Mathematics
1 answer:
TEA [102]3 years ago
3 0
Yes because 3² + 4² = 5²


to be sure

9 + 16 = 25

25 = 25
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We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal
ohaa [14]

Answer: AAA similarity.


Step-by-step explanation:  CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

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Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.


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3 years ago
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3 years ago
Which of the following is a solution to 2cos^2x– 2 = 0 ?
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