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sergiy2304 [10]
3 years ago
13

A ball is thrown into the air from the roof of a building that is 25

Mathematics
1 answer:
guapka [62]3 years ago
6 0

See https://web2.0calc.com/questions/help_29603.

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0.11 as a fraction and in the simplest form
vovangra [49]
Considering that the last 1 in 0.11 is located in the hundredths place, the simplest from of this fraction is 11/100 because it cannot be reduced.

*If you have any questions, feel free to ask me! I'd be happy to help you anytime!
5 0
3 years ago
Read 2 more answers
Point D is the midpoint of HJ. Point D is located at (-3,4) and point H is located at (9,-6). Where is point J located?
bekas [8.4K]

Answer:

-15,14

Step-by-step explanation:

5 0
3 years ago
Unit 3 parallel and perpendicular lines homework 4 parallel line proofs
Alex17521 [72]

Answer:

1) c ║ d by consecutive interior angles theorem

2) m∠3 + m∠6 = 180° by transitive property

3) ∠2 ≅ ∠5 by definition of congruency

4) t ║ v                                    {}                   Corresponding angle theorem

5) ∠14 and ∠11  are supplementary         {}  Definition of supplementary angles

6) ∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem

Step-by-step explanation:

1) Statement                                {}                                     Reason

m∠4 + m∠7 = 180°                                 {}   Given

m∠4 ≅ m∠6                                {}              Vertically opposite angles

m∠4 = m∠6                               {}                Definition of congruency

m∠6 + m∠7 = 180°                                {}    Transitive property

m∠6 and m∠7 are supplementary     {}     Definition of supplementary angles

∴ c ║ d                               {}                       Consecutive interior angles theorem

2) Statement                                {}                                     Reason

m∠3 = m∠8                                 {}           Given

m∠8 + m∠6 = 180°                {}                 Sum of angles on a straight line

∴ m∠3 + m∠6 = 180°               {}               Transitive property

3) Statement                                {}                                     Reason

p ║ q                                 {}                    Given

∠1 ≅ ∠5                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠2 ≅ ∠1                               {}                  Alternate interior angles theorem

∠2 = ∠1                               {}                   Definition of congruency

∠2 = ∠5                                  {}               Transitive property

∠2 ≅ ∠5                                  {}              Definition of congruency.

4) Statement                                {}                                     Reason

∠1 ≅ ∠5                                  {}                Given

∠3 ≅ ∠4                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠3 = ∠4                               {}                  Definition of congruency

∠5 ≅ ∠4                               {}                 Vertically opposite angles

∠5 = ∠4                               {}                  Definition of congruency

∠5 = ∠3                                  {}               Transitive property

∠1 = ∠3                                  {}                Transitive property

∠1 ≅ ∠3                                  {}                Definition of congruency.

t ║ v                                    {}                   Corresponding angle theorem

5) Statement                                {}                                     Reason

∠5 ≅ ∠16                                  {}              Given

∠2 ≅ ∠4                               {}                  Given

∠5 = ∠16                               {}                  Definition of congruency

∠2 = ∠4                               {}                   Definition of congruency

EF ║ GH                               {}                  Corresponding angle theorem

∠14 ≅ ∠16                               {}                Corresponding angles

∠14 = ∠16                               {}                 Definition of congruency

∠5 = ∠14                                  {}               Transitive property

∠5 + ∠11 = 180°                {}                       Sum of angles on a straight line

∠14 + ∠11 = 180°                                {}      Transitive property

∠14 and ∠11  are supplementary         {}  Definition of supplementary angles  

6) Statement                                {}                                     Reason

l ║ m                                 {}                      Given

∠4 ≅ ∠7                               {}                  Given

∠4 = ∠7                               {}                   Definition of congruency

∠2 ≅ ∠7                               {}                  Alternate angles

∠2 = ∠7                               {}                   Definition of congruency

∠2 = ∠4                                  {}               Transitive property

∠2 ≅ ∠4                               {}                  Definition of congruency

∠2 and ∠4 are corresponding angles   {} Definition

DA ║ EB                               {}                  Corresponding angle theorem

∠8 and ∠9  are consecutive  interior angles    {} Definition

∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem.

6 0
3 years ago
Evaluate i^31 please help
Nadya [2.5K]

ANSWER

{i}^{31}  =  - i

EXPLANATION

We want to evaluate

{i}^{31}

Use indices to rewrite the expression as:

=  {i}^{30}  \times i

We know that

{i}^{2}  =  - 1

So we rewrite the expression to obtain;

=  ({ {i}^{2}) }^{15}  \times i

This gives us;

=   {( - 1) }^{15}  \times i

This simplifies to

=  - 1 \times i

=  - i

4 0
3 years ago
Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =
Elza [17]
Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
 \sin B=\frac{opposite}{hypotenuse} = \frac{3}{5} and
 \cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}.

Since O lies in second quadrant \cos O\ \textless \ 0 and 
\cos O= -\cos B =- \frac{4}{5}.
Answer: \cos O=- \frac{4}{5}. 


3 0
4 years ago
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