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3 years ago

A ball is thrown into the air from the roof of a building that is 25

Mathematics

1 answer:

guapka [62]3 years ago

6 0

See https://web2.0calc.com/questions/help_29603.

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What is the distance between the point (−10, −2)(−10, −2) and the point (−4, −2)(−4, −2) ?

Gnoma [55]

In this case: x 1 = - 10, y 1 = - 2;
x 2 = - 4 , y 2 = - 2
The distance between the points :
$d = \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\ =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2} } = \sqrt{36}= 6$
Answer: d = 6

4 0

3 years ago

Read 2 more answers

A box office sold 147,523 tickets for an auto race.

Marysya12 [62]

Answer:

78,799 children's tickets

Step-by-step explanation:

147,523 total tickets, 68,724 adult tickets

Subtract to find amount of children's tickets:

147,523-68,724 = 78,799

5 0

3 years ago

How much bigger is the largest bowl than the smallest bowl?

dmitriy555 [2]

Answer:

5/8

Step-by-step explanation:

The biggest bowl Mr. Ramsey bought is 7/8, and the smallest is 2/8.

Thus, 7/8 - 2/8 = 5/8 quarts.

6 0

2 years ago

Read 2 more answers

i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR

Veseljchak [2.6K]

Answer:

The area of the rectangle TOUR is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

$Area\ of\ a\ Rectangle=length\times width$

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Considering the rectangle TOUR the area formula will be:

Area of Rectangle TOUR = TO × OU

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices T and O as:

$TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}$

Compute the distance between the vertices O and U as:

$OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}$

Compute the area of rectangle TOUR as follows:

$Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}$

Thus, the area of the rectangle TOUR is 80.00 unit².

6 0

3 years ago

Pls help will give brainiest and 5star plss help

saul85 [17]

Answer:

Type in AR, DQ,BS, CP, It's tilted sideways.

Step-by-step explanation:

6 0

3 years ago