Giving out the 15 points help please number 2.

A vineyard has 145 acres of Chardonnay grapes. A particular soil supplement requires 5.50 grams for every square meter of vineya

SashulF [63]

3230 kilograms of the soil supplement are required for the entire vineyard

<h3>Further explanation</h3>

Some units that need to be recalled are as follows :

<em>1 km² = 247 acres</em>

Let's tackle the problem now!

A vineyard has 145 acres of Chardonnay grapes.

$145 ~ acres = \frac{145}{247} \times 1 ~ km^2$

$145 ~ acres = \frac{145}{247} ~ km^2$

$\boxed {145 ~ acres \approx 0.587 ~ km^2}$

A particular soil supplement requires 5.50 grams for every square meter of vineyard.

$1 ~ m^2 \rightarrow 5.50 ~ gram$

$1 ~ km^2 = 10^6 ~ m^2 \rightarrow 5.50 \times 10^6 ~ gram$

$1 ~ km^2 \rightarrow 5.50 \times 10^6 \times 10^{-3} ~ kg$

$\boxed {1 ~ km^2 \rightarrow 5.50 \times 10^3 ~ kg}$

$145 ~ acres = \frac{145}{247} ~ km^2 \rightarrow \frac{145}{247} \times 5.50 \times 10^3 ~ kg$

$145 ~ acres \rightarrow \frac{797500}{247} ~ kg$

$145 ~ acres \rightarrow 3230 ~ kg$

<h2>Conclusion :</h2>

It required 797500/247 kg ≈ 3230 kg of the soil supplement for the entire vineyard

<h3>Learn more</h3>

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<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Arithmetic

Keywords: Addition , Subtraction , Multiplication , Division , Number , Expression , Time , Duration , Write

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Answer:

the answer is B

Step-by-step explanation:

since one equation is already simplified then you shall plug in the other equation into the other to substitute and simplify

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Which of the following are solutions to the equation below

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The answers are A and E.
The factors are (2x +9)(2x-9). If you solve each one by equaling each one to zero. You will get:
2x+9=0 2x-9=0
x=-9/2 x=9/2

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Calculate the velocity of a moving train with a mass 10,000kg and 150,000J of energy.

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Kinetic energy possessed by moving train is $E_k = 150000J$ .

And mass $m = 10000kg$ .

The formula for kinetic energy is $E_k = \frac{m\times v^2}{2}$ .

Solve for velocity:

$E_k = \frac{m\times v^2}{2}\implies 2E_k = m\times v^2$

$v^2=\frac{2E_k}{m}\implies \underline{v = \sqrt{\frac{2E_k}{m}}}$

Now put in the data:

$v = \sqrt{\frac{2\times150000J}{10000kg}}\approx5.48\frac{m}{s}$

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Step-by-step explanation:

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