Answer:
The two integers the square root of 62 falls between are 7, and 8.
Step-by-step explanation:
the square root of 62 is 7.874.... so the numbers that it is between are 7 and 8 because its more than 7 but less than 8
This can be solved using a ratio. The ratio is: 13/20=x/60 this would then become 20x= 780 divide both sides by 20 and you get x=39. the answer is 39
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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Answer:
The answer simplify is 16384
Step-by-step explanation:
