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3 years ago

Which figure has two circular faces?

Mathematics

2 answers:

Vladimir79 [104]3 years ago

7 0

Answer:

Figure A

Step-by-step explanation:

Hope it helps.

zhannawk [14.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

Figure A, which also happens to be option A ✨✨✨✨

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Find the product: <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20%20%5Ctimes%20%20%5Csqrt%7B8%7D%20" id="TexFo

lozanna [386]

Answer:

≈ 0.35

Step-by-step explanation:

First simplify $\sqrt{8}$ and $\frac{1}{8}$ :

$\sqrt{8}$ ≈ 2.83

$\frac{1}{8}$ = 0.125

Now multiply them as shown in the original equation:

0.125 x 2.83 = 0.35375 ≈ 0.35

5 0

2 years ago

The general manager, marketing director, and 3 other employees of CompanyAare hosting a visitby the vice president and 2 other e

zubka84 [21]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Let, In the Bth place there are 8 values.

In point a:

There is no case, where it generally manages its next groom is = 7 and it will be arranged in the 2, that can be arranged in 2! ways. So, the total number of ways are: $\to 7 \times 2= 14\\\\ \{(1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5),(6,7),(7,8),(8,7),(7,6)\}\\$ $\therefore$ required probability:

$= \frac{14}{8!}\\\\= \frac{14}{8\times7 \times6 \times 5 \times 4 \times 3\times 2 \times 1 }\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\=\frac{1}{2880}\\\\=0.00034$

In point b:

Calculating the leftmost position:

$\to \frac{7!}{8!}\\\\\to \frac{7!}{8 \times 7!}\\\\\to \frac{1}{8}\\\\\to 0.125$

In point c:

This option is false because

$\to P(A \cap B) \neq P(A) \times P(B)\\\\\to \frac{12}{8!} \neq \frac{14}{8!}\times \frac{1}{8}\\\\\to \frac{12}{8!} \neq \frac{7}{8!}\times \frac{1}{4}\\\\$

3 0

3 years ago

Diameter of the circle whose radius is given a) 3.5cm

sdas [7]

To find the diameter of the radius you need to multiply 3.5 x 2 = 7

5 0

3 years ago

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

What is the interest rate? A) 1 B) 2 C) 4 D) 300

liubo4ka [24]

Answer:

I need more information to calculate it for you

5 0

3 years ago

Read 2 more answers