sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule, 
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
Answer:
4 sets of 25
Step-by-step explanation:
100/25 = 4
Not sure what you are asking in the end.
336" - You are to times all of them together to get your answer. Dont forget to put the inches.
The larger one is (-11 + 41)/2 = 15.
The smaller one is (-11 -41)/2 = -26.
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For two numbers a and b with sum s and difference d, you can write the equations
Then adding the equations and dividing that sum by 2, you get
You can subtract the second eqution from the first and get a similar result for the smaller number
These are the formulas we used above.
