No sure I used Photomath hope it’s a start
Complete question :
A company is manufacturing highway emergency ares. Such ares are sup- posed to burn for an average of 20 minutes. Every hour a sample of ares is collected, and their average burn time is determined. If the manufacturing process is working cor- rectly, there is a 68% chance that the average burn time of the sample will be between 14 minutes and 26 minutes. The quality engineer in charge of the process believes that if 4 of 5 samples fall outside these bounds then this is a signal that the process might not be performing as expected. Each morning the sampling begins anew. Let X denote the number of samples drawn in order to obtain the fourth sample whose average value is outside of the above bounds. Find the probability that for a given morning X = 5, hence there seems to be a problem right away.
Answer:
0.0285
Step-by-step explanation:
We are to find the probability for a given morning that X = 5
From the question, we could see that there is a 68% chance that the average burn time of the sample will be between 14 minutes and 26 minutes and the success of the process is obtained after the fourth or fifth sample.
Thus, r = 4; q = 0.68
The probability average burn time falls outside p will be:
p = 1 - 0.68 = 0.32
The random variable X follows negative binomial distribution.
Therefore,
Where, x = 5
r = 4
p = 0.32
Substituting figures in the equation, we have:
= 0.0285
The probability that for a given morning X = 5 is 0.0285
2/7=0.2857142857
1/3=0.3333
A rational number is that number that can be expressed as a ratio of 2 integers.
The 5 numbers could be:
0.29=29/100
0.3=3/10
0.31=31/100
0.32=32/100=8/25
0.33=33/100
These numbers are not unique.
Ok, hmm
possible ones are
starting with 8 or 9
adds to 13
8+5=13
9+4=13
thepossible numbers are 85 and 94
tens is 3 more than ones digit
8-5=3 true
9-4=5, not what we looking for
aswer is 85
Answer:
<h2>In this case,the answer would be option d) given in the answer choices or options or A two-sample t-test for a difference between population means.</h2>
Step-by-step explanation:
- In Statistics,a two sample test is generally used to examine or compare two different population means with the main objective to verify whether the population means are equal or otherwise.
- The two sample t-test basically involves the hypothesis testing to determine or verify the equality between two concerned population means.
- In this case,the two different populations of raccoons are given and the equality of the mean sample weights of the two distinct populations can be determined or evaluated by employing the hypothesis testing method under a two sample t test for measuring difference in two population means.