Answer:
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.
The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Approx - 10%
72 students signed up for canoeing + the 23 students who signed up for trekking + the 13 students who signed up for both = 108 students
there are 120 students total, so you have to subtract 120 - 108 = 12
Now to find the percentage, you have to divide the number of students who didn't sign up for either, by the total
which is .1 = 10/100 = 10%
D. -2, if the lines are parallel then the slope is the same but the y-int is different
Answer:
c.
............
..............................
To solve the problem we must know the basic exponential properties.
<h3>What are the basic exponent properties?</h3>


![\sqrt[m]{a^n} = a^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D%20%3D%20a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)


The expression can be written as
.
Given to us

Using the exponential property
,

Using the exponential property
,
![=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}](https://tex.z-dn.net/?f=%3Dx%5E9%5Ctimes%20y%5E%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%3Dx%5E9%5Ctimes%20%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C%3Dx%5E9%20%5Csqrt%5B3%5D%7By%7D)
Hence, the expression can be written as
.
Learn more about Exponent properties:
brainly.com/question/1807508