1. Over a period of 6 years (from 1980 to 1986) the house gained a value of 12000 dollars (109k-97k). 12000/6 gives you a rate of 2000 dollars per year. Because the initial price at t=0 is 97000, the function is 97000+2000t
Answer:
θ is decreasing at the rate of
units/sec
or
(θ) = 
Step-by-step explanation:
Given :
Length of side opposite to angle θ is y
Length of side adjacent to angle θ is x
θ is part of a right angle triangle
At this instant,
x = 8 ,
= 7
(
denotes the rate of change of x with respect to time)
y = 8 ,
= -14
( The negative sign denotes the decreasing rate of change )
Here because it is a right angle triangle,
tanθ =
-------------------------------------------------------------------1
At this instant,
tanθ =
= 1
Therefore θ = π/4
We differentiate equation (1) with respect to time in order to obtain the rate of change of θ or
(θ)
(tanθ) =
(y/x)
( Applying chain rule of differentiation for R.H.S as y*1/x)
θ
(θ) = 
- 
-----------------------2
Substituting the values of x , y ,
,
, θ at that instant in equation (2)
2
(θ) =
*(-14)-
*7
(θ) = 
Therefore θ is decreasing at the rate of
units/sec
or
(θ) = 
Given:
Reserve requirement = 10%
Deposit = $5400
Find:
money the supply could expand = ?
Solution:
Money Supply =
Monetary Base × Money Multiplier
Before we determine the money supply, the money multiplier must
already be determined. Therefore:
$5400 (0.10) = $540
In this case, adding the two will give us the money supply
$5400 + $540 = $5940
Nevertheless, not all money is lent out or spent. Kept money
reduces the money supply.
The restrain to the growth of the money supply when deposits
expand are identified by 2 factors:
1.
The amount above (excess reserves) what they are
required to hold are being kept.
2.
Their income rises as the public has the
penchant to hold more cash as their income.
Answer:
the three consecutive odd integers are 9, 11, and 13.
Step-by-step explanation:
Let's say that the first odd integer is x. The second consecutive odd integer would have to be x+2. (It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2) +2 or x+4.
The sum of the first, twice the second, and three times the third can be written as:
x+2(x+2)+3(x+4)
This equals 70. We can now distribute and solve for x:
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70(distribute)
6x+16=70(combine like terms)
6x=54(subtract 16 from both sides)
x=9(divide by 9)
Thus, the three consecutive odd integers are 9, 11, and 13
hope this helps :)