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EastWind [94]
3 years ago
14

I know the right answer to this I just don't know how to get it, please help.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
\bf \cfrac{x^2+5x+6}{x+4}\cdot \cfrac{x^2+x-12}{x^2+x-2}\implies \cfrac{\underline{(x+2)}(x+3)}{\underline{x+4}}\cdot \cfrac{\underline{(x+4)}(x-3)}{\underline{(x+2)}(x-1)}
\\\\\\
\cfrac{(x+3)(x-3)}{x-1}

and yes, the restrictions are -4, -2 and 1.

the original expression has such restrictions because if ever "x" becomes one of those values, one of the denominators will turn to 0 making the fraction undefined.
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I need help again.lol
Monica [59]

Answer:

13\ units

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

Where ((x_1,y_1)) and ((x_2,y_2)) are the points which one needs to find the distance between. In this case, these points are as follows:

k\ (-3,5)

j\ (-8, -7)

Substitute these points into the formula and solve for the distance between these points,

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

Simplify,

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

D=\sqrt{(-3+8)^2+(5+7)^2

D=\sqrt{(5)^2+(12)^2

D=\sqrt{25+144}

D=\sqrt{169}

D=13

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