First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62
now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407
Answer: The possible side lengths are either 16 inches or 20 inches
Step-by-step explanation: The aquarium is in the shape of a cube which suggests that, all dimensions (length, width and height) are equal.
If it can hold 4096 cubic inches of water, then the volume of water in it can be calculated as follows;
Volume = L x W x H
Knowing that all three dimensions are the same the formula can be re-written as;
Volume = L³
4096 = L³
Add the cube root sign to both sides of the equation
∛4096 = ∛L³
16 = L
Also if it can hold up to 8000 cubic inches of water, then the volume of water in it can be calculated as;
Volume = L³
8000 = L³
Add the cube root sign to both sides of the equation
∛8000 = ∛L³
20 = L
Therefore, if the aquarium can hold between 4096 and 8000 cubic inches of water, then the side lengths are either 16 inches or 20 inches
..........................................
Where is the problem that we have to solve
Answer:
It should be 46.20
Step-by-step explanation:
You're rounding to the nearest hundredth. So you have 46.1979 to start out with. Then you count 2 places so you end at the 1st 9. Well, behind the 9 is a 7 so you round up and get 20
