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lukranit [14]
3 years ago
11

If the area of a trapezoid is 234 square units what is the value of x

Mathematics
2 answers:
olganol [36]3 years ago
6 0
h=9
A=((a+b)/2)h
234=((32+20)/2)h
234=(52/2)h
234=26h
9=h

lara31 [8.8K]3 years ago
6 0

Answer:9




Step-by-step explanation:


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Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

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Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

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Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

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