S = 4LW + 2WH; S = 168, L = 8, W = 4 H=

Rainbow [258]

Answer:

The answer is below

Step-by-step explanation:

Let B represent those that like badminton, F represent those that like football and V represent those that like volleyball. Let x represent the total number of people.

n(B) = (1/3)x, n(F) = (3/4)x, n(V) = (5/6)x

n(B∩F∩V) = 20% of x = 0.2x

n(B∩F) = 17, hence n(B∩F∩V') = 17 - 0.2x

n(V∩F) = 60, hence n(B'∩F∩V) = 60 - 0.2x

n(B∩V) = 65, hence n(B∩F'∩V) = 65 - 0.2x

n(B∪F∪V)' = 8

n(B∩F'∩V') = (1/3)x - 0.2x - (17 - 0.2x) - (65 - 0.2x) = 0.533x - 82

n(B'∩F∩V') = (3/4)x - 0.2x - (17 - 0.2x) - (60 - 0.2x) = 0.95x - 77

n(B'∩F'∩V) = (5/6)x - 0.2x - (60 - 0.2x) - (65 - 0.2x) = 1.033x - 125

Therefore:

x = n(B∩F'∩V') + n(B'∩F∩V') + n(B'∩F'∩V) + n(B∩F∩V) + n(B∩F∩V') + n(B'∩F∩V) + n(B∩F'∩V) + n(B∪F∪V)'

x = (0.533x - 82) + (0.95x - 77) + (1.033x - 125) + (0.2x) + (17 - 0.2x) + (60 - 0.2x) + (65 - 0.2x) + 8

x = 2.1166x - 134

1.1166x = 134

x = 120

Therefore there was 120 students

4 0

3 years ago

Columbus Ohio Population: 8.23 * 10^5

MakcuM [25]

This is Scientific Notation here's what you have to do:

First find the Notation:

8.23×10^5

It positive so go to the right.

=823000.

Next do the same thing but with the next Notation:

3.19×10^8

Its positive so go to the right:

=319000000.

Then compare the Notation's

823000. and 319000000.

319000000. is bigger than 823000.

So your answer is 319000000. so its United States.

8 0

4 years ago

The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is

Hatshy [7]

Answer:

A. Normal

B. 30.1, 32.9

C. 95, 5

Step-by-step explanation:

A. The sampling distribution follows a normal distribution

Given that the sample size is large, we have that the sample distribution follows a normal distribution according to the central limit theorem

B. The 95% confidence interval is given as follows;

$CI=\bar{x}\pm z \times \dfrac{s}{\sqrt{n}}$

The number of residents in the study, n = 120 residents

The sample mean, $\overline x$ = 31.5 pounds

The standard deviation, s = 7.8 pounds

The z-value for 95% confidence level, z = 1.96

Therefore, we get;

C.I. = 31.5 ± 1.96 × 7.8/√(120)

The 95% C.I. ≈ 30.1 ≤ $\overline x$ ≤ 32.9

Therefore, we have that with 95% confidence, the population mean number of pounds per person per week is between 30.1 and 32.9

C. Therefore, according to the central limit theorem, about 95 percent of the groups of 120 will contain the true population mean number of pounds of trash generated per person per week and about 5 percent will not contain the true population mean number of pounds of trash generated per person per week.

8 0

3 years ago

Write an equation that can determine the cost for any number of pounds of strawberries purchased.

hjlf

Answer:

y=2.5x

Step-by-step explanation:

To get the equation in y = mx + b format, we need to find m and b, the slope and y-intercept.

To find the slope, we need two points on a graph, which we have.

First, the slope

The formula for slope is

$\frac{y2-y1}{x2-x1}$

Our points, (6, 15) and (2, 5)

Plugging into our equation:

$\frac{15 - 5}{6 - 2}$ , which is 10 divided by 4, which is 2.5

Our equation now:

$y=2.5x+b$

To find our b, we need to plug in one x value.

(6, 15) are our pair of points.

6 = x

15 = y

$15 = 6(2.5) + b$ =>

$15 = 15+b$ =>

$b = 0$

If b is 0, then we don't need to include b.

Our equation is $y=2.5x$

5 0

3 years ago

You use a line of best fit for a set of data to make a prediction about an unknown value. The correlation coefficient for your d

Trava [24]

Answer:

Following are the solution to this question:

Step-by-step explanation:

For this set, the correlation coefficient is = -0.015.

It shows that financial variables have trust issues. Once a price rises, the other one is decreasing the value of -0,015 shows, that there are several fewer associations in the set of data among x and y and between y values. This interaction also can range between -1 to 1, to 0 being completely unrelated. But you'd never be sure, in this situation, 0.015 is very similar to 0.

It means that your prediction is nothing better than just a wild choice. Its odds of an estimated value being relatively close to the actual result are therefore much smaller as the points are it's hardly the best match.

4 0

3 years ago